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modificato script cronexec per non loggare in syslog ed utilizzare

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invece il task log dell'applicazione
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Riccardo Di Dato
2016-05-12 16:42:49 +02:00
parent 693b3acde4
commit 2c741c96e1
1 changed files with 6 additions and 6 deletions
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private/bin/cronexec
+6 -6
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@@ -7,29 +7,29 @@ LOG_PREFIX="$APPLICATION_BUILDNAME-CRONEXEC"
if [ -z "$1" ];
then
logger "$LOG_PREFIX ERROR!!! Missing time specifier"
echo "$LOG_PREFIX ERROR!!! Missing time specifier" >> "$APPLICATION_LOG_PATH/task.log"
exit 1
fi
if [ "$1" == "5minutes" ] || [ "$1" == "minute" ] || [ "$1" == "daily" ] || [ "$1" == "hourly" ] || [ "$1" == "monthly" ] || [ "$1" == "weekly" ];
then
logger "$LOG_PREFIX Executing '$1' tasks"
echo "$LOG_PREFIX Executing '$1' tasks" >> "$APPLICATION_LOG_PATH/task.log"
BASEDIR=`pwd`
cd "$APPLICATION_CRON_PATH"
for i in `ls | grep -P "\.$1\."`
do
logger "$LOG_PREFIX Executing '$i' task"
echo "$LOG_PREFIX Executing '$i' task" >> "$APPLICATION_LOG_PATH/task.log"
RESULT=`./$i`
if [[ "$RESULT" = "" ]]; then
logger "$LOG_PREFIX Execution of task '$i' completed"
echo "$LOG_PREFIX Execution of task '$i' completed" >> "$APPLICATION_LOG_PATH/task.log"
else
logger "$LOG_PREFIX Task '$i' returned message '$RESULT'"
echo "$LOG_PREFIX Task '$i' returned message '$RESULT'" >> "$APPLICATION_LOG_PATH/task.log"
fi
done
cd "$BASEDIR"
else
logger "$LOG_PREFIX ERROR!!! Invalid time specifier"
echo "$LOG_PREFIX ERROR!!! Invalid time specifier" >> "$APPLICATION_LOG_PATH/task.log"
exit 1
fi